In a bizarre sequence during Monday's game, the Boston Red Sox scored a run in the seventh inning even though the Toronto Blue Jays recorded three outs. The unusual play occurred when a Blue Jays fielder caught a line drive and then threw to second base, doubling off a runner, and then to first, completing a triple play. However, the Red Sox challenged the play, and after review, the umpires ruled that the runner from third base had crossed the plate before the third out was recorded at first base.
According to MLB Rule 5.08, a run counts if it scores before the third out, unless the third out is a force out or occurs on a batter-runner before reaching first base. In this case, the third out was a tag out at first base, not a force out, so the run counted. The Red Sox were awarded the run, making the score 4-3 in favor of Boston at that point.
The play was reminiscent of a similar incident in 2019 when the New York Yankees scored a run after a triple play against the Red Sox. In that game, the umpires also ruled that the run scored before the third out, leading to a lengthy review and confusion among players and fans.
The Red Sox went on to win the game 5-3, with the controversial run proving to be the difference. Blue Jays manager John Schneider argued the call but to no avail, as the umpires upheld the decision after review.
